Base | Representation |
---|---|
bin | 110001010111000100… |
… | …111101111011000011 |
3 | 12001210200211202122001 |
4 | 301113010331323003 |
5 | 1332021113340210 |
6 | 40203105124431 |
7 | 3554255023333 |
oct | 612704757303 |
9 | 161720752561 |
10 | 53000527555 |
11 | 20528463898 |
12 | a331929717 |
13 | 4cc85aa411 |
14 | 27cb0330c3 |
15 | 15a2ee003a |
hex | c5713dec3 |
53000527555 has 8 divisors (see below), whose sum is σ = 63604659312. Its totient is φ = 42397737888.
The previous prime is 53000527529. The next prime is 53000527561. The reversal of 53000527555 is 55572500035.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 53000527555 - 221 = 52998430403 is a prime.
It is a super-2 number, since 2×530005275552 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 246492 + ... + 408361.
It is an arithmetic number, because the mean of its divisors is an integer number (7950582414).
Almost surely, 253000527555 is an apocalyptic number.
53000527555 is a deficient number, since it is larger than the sum of its proper divisors (10604131757).
53000527555 is a wasteful number, since it uses less digits than its factorization.
53000527555 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 671045.
The product of its (nonzero) digits is 131250, while the sum is 37.
The spelling of 53000527555 in words is "fifty-three billion, five hundred twenty-seven thousand, five hundred fifty-five".
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