53000553331 has 4 divisors (see below), whose sum is σ = 57818785464. Its totient is φ = 48182321200.

The previous prime is 53000553299. The next prime is 53000553341. The reversal of 53000553331 is 13335500035.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 53000553331 - 2⁵ = 53000553299 is a prime.

It is a super-2 number, since 2×53000553331² (a number of 22 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 53000553331.

It is not an unprimeable number, because it can be changed into a prime (53000553341) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2409116050 + ... + 2409116071.

It is an arithmetic number, because the mean of its divisors is an integer number (14454696366).

Almost surely, 2^53000553331 is an apocalyptic number.

53000553331 is a deficient number, since it is larger than the sum of its proper divisors (4818232133).

53000553331 is a wasteful number, since it uses less digits than its factorization.

53000553331 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4818232132.

The product of its (nonzero) digits is 10125, while the sum is 28.

The spelling of 53000553331 in words is "fifty-three billion, five hundred fifty-three thousand, three hundred thirty-one".