Base | Representation |
---|---|
bin | 111100010000010101101011… |
… | …0010110101111101000001011 |
3 | 2120111121120102100222220110011 |
4 | 1320200223112112233220023 |
5 | 1023432200314020004332 |
6 | 5115123432231532351 |
7 | 216432020253546631 |
oct | 17040532626575013 |
9 | 2514546370886404 |
10 | 530011150547467 |
11 | 143972515138206 |
12 | 4b53b865b2a0b7 |
13 | 19997ab5c8b704 |
14 | 94c49686a5351 |
15 | 4141c165a2e47 |
hex | 1e20ad65afa0b |
530011150547467 has 4 divisors (see below), whose sum is σ = 530615496216016. Its totient is φ = 529406804878920.
The previous prime is 530011150547453. The next prime is 530011150547497. The reversal of 530011150547467 is 764745051110035.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 530011150547467 - 27 = 530011150547339 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 530011150547467.
It is not an unprimeable number, because it can be changed into a prime (530011150547497) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 302172832959 + ... + 302172834712.
It is an arithmetic number, because the mean of its divisors is an integer number (132653874054004).
Almost surely, 2530011150547467 is an apocalyptic number.
530011150547467 is a deficient number, since it is larger than the sum of its proper divisors (604345668549).
530011150547467 is an equidigital number, since it uses as much as digits as its factorization.
530011150547467 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 604345668548.
The product of its (nonzero) digits is 1764000, while the sum is 49.
The spelling of 530011150547467 in words is "five hundred thirty trillion, eleven billion, one hundred fifty million, five hundred forty-seven thousand, four hundred sixty-seven".
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