530030433 has 4 divisors (see below), whose sum is σ = 706707248. Its totient is φ = 353353620.

The previous prime is 530030401. The next prime is 530030461. The reversal of 530030433 is 334030035.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 530030433 - 2⁵ = 530030401 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (530035433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 88338403 + ... + 88338408.

It is an arithmetic number, because the mean of its divisors is an integer number (176676812).

Almost surely, 2^530030433 is an apocalyptic number.

It is an amenable number.

530030433 is a deficient number, since it is larger than the sum of its proper divisors (176676815).

530030433 is a wasteful number, since it uses less digits than its factorization.

530030433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 176676814.

The product of its (nonzero) digits is 1620, while the sum is 21.

The square root of 530030433 is about 23022.3898194779. The cubic root of 530030433 is about 809.2827227386.

Adding to 530030433 its reverse (334030035), we get a palindrome (864060468).

The spelling of 530030433 in words is "five hundred thirty million, thirty thousand, four hundred thirty-three".