Base | Representation |
---|---|
bin | 111100010000011111100111… |
… | …1000101011011101111111001 |
3 | 2120111200121112111011111010020 |
4 | 1320200333033011123233321 |
5 | 1023433023031332434221 |
6 | 5115141323125441053 |
7 | 216433404354054342 |
oct | 17040771705335771 |
9 | 2514617474144106 |
10 | 530032503405561 |
11 | 143980582287572 |
12 | 4b543a24b70189 |
13 | 19999b09a1a5a0 |
14 | 94c59d250b0c9 |
15 | 4142565ea0ac6 |
hex | 1e20fcf15bbf9 |
530032503405561 has 16 divisors (see below), whose sum is σ = 761078678989440. Its totient is φ = 326171119789440.
The previous prime is 530032503405533. The next prime is 530032503405571. The reversal of 530032503405561 is 165504305230035.
It is not a de Polignac number, because 530032503405561 - 218 = 530032503143417 is a prime.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (530032503405571) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 52115916 + ... + 61450253.
It is an arithmetic number, because the mean of its divisors is an integer number (47567417436840).
Almost surely, 2530032503405561 is an apocalyptic number.
It is an amenable number.
530032503405561 is a deficient number, since it is larger than the sum of its proper divisors (231046175583879).
530032503405561 is a wasteful number, since it uses less digits than its factorization.
530032503405561 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 113685856.
The product of its (nonzero) digits is 810000, while the sum is 42.
Adding to 530032503405561 its reverse (165504305230035), we get a palindrome (695536808635596).
The spelling of 530032503405561 in words is "five hundred thirty trillion, thirty-two billion, five hundred three million, four hundred five thousand, five hundred sixty-one".
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