530050414130113 has 4 divisors (see below), whose sum is σ = 530050533452740. Its totient is φ = 530050294807488.

The previous prime is 530050414130051. The next prime is 530050414130123. The reversal of 530050414130113 is 311031414050035.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 526642280921344 + 3408133208769 = 22948688^2 + 1846113^2 .

It is a cyclic number.

It is not a de Polignac number, because 530050414130113 - 2⁴⁵ = 494866042041281 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (530050414130123) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 52729620 + ... + 61971877.

It is an arithmetic number, because the mean of its divisors is an integer number (132512633363185).

Almost surely, 2^{530050414130113} is an apocalyptic number.

It is an amenable number.

530050414130113 is a deficient number, since it is larger than the sum of its proper divisors (119322627).

530050414130113 is a wasteful number, since it uses less digits than its factorization.

530050414130113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 119322626.

The product of its (nonzero) digits is 10800, while the sum is 31.

Adding to 530050414130113 its reverse (311031414050035), we get a palindrome (841081828180148).

The spelling of 530050414130113 in words is "five hundred thirty trillion, fifty billion, four hundred fourteen million, one hundred thirty thousand, one hundred thirteen".