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53005255555003 = 139381332773777
BaseRepresentation
bin11000000110101001111110…
…11011011011011110111011
320221200020211101200101201021
430003110333123123132323
523421414230410230003
6304422140033403311
714110334434232053
oct1403247733333673
9227606741611637
1053005255555003
1115986447a0a054
125b40934a09537
1323764b301a72b
14d1367a4c6563
1561dbc598a2bd
hex30353f6db7bb

53005255555003 has 4 divisors (see below), whose sum is σ = 53386588328920. Its totient is φ = 52623922781088.

The previous prime is 53005255554959. The next prime is 53005255555019. The reversal of 53005255555003 is 30055555250035.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 53005255555003 - 233 = 52996665620411 is a prime.

It is a super-4 number, since 4×530052555550034 (a number of 56 digits) contains 4444 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (53005255585003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 190666386750 + ... + 190666387027.

It is an arithmetic number, because the mean of its divisors is an integer number (13346647082230).

Almost surely, 253005255555003 is an apocalyptic number.

53005255555003 is a deficient number, since it is larger than the sum of its proper divisors (381332773917).

53005255555003 is a wasteful number, since it uses less digits than its factorization.

53005255555003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 381332773916.

The product of its (nonzero) digits is 1406250, while the sum is 43.

The spelling of 53005255555003 in words is "fifty-three trillion, five billion, two hundred fifty-five million, five hundred fifty-five thousand, three".

Divisors: 1 139 381332773777 53005255555003