Base | Representation |
---|---|
bin | 1100101000110… |
… | …1111001110001 |
3 | 10200202012002120 |
4 | 3022031321301 |
5 | 102032310113 |
6 | 5132104453 |
7 | 1212402126 |
oct | 312157161 |
9 | 120665076 |
10 | 53010033 |
11 | 27a1724a |
12 | 15905129 |
13 | aca04ab |
14 | 707c74d |
15 | 49c1a23 |
hex | 328de71 |
53010033 has 4 divisors (see below), whose sum is σ = 70680048. Its totient is φ = 35340020.
The previous prime is 53009987. The next prime is 53010053. The reversal of 53010033 is 33001035.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 53010033 - 214 = 52993649 is a prime.
It is a super-2 number, since 2×530100332 = 5620127197322178, which contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 53009994 and 53010021.
It is not an unprimeable number, because it can be changed into a prime (53010053) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8835003 + ... + 8835008.
It is an arithmetic number, because the mean of its divisors is an integer number (17670012).
Almost surely, 253010033 is an apocalyptic number.
It is an amenable number.
53010033 is a deficient number, since it is larger than the sum of its proper divisors (17670015).
53010033 is a wasteful number, since it uses less digits than its factorization.
53010033 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 17670014.
The product of its (nonzero) digits is 135, while the sum is 15.
The square root of 53010033 is about 7280.7989259421. The cubic root of 53010033 is about 375.6522763260.
Adding to 53010033 its reverse (33001035), we get a palindrome (86011068).
The spelling of 53010033 in words is "fifty-three million, ten thousand, thirty-three".
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