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53010041 = 77572863
BaseRepresentation
bin1100101000110…
…1111001111001
310200202012002212
43022031321321
5102032310131
65132104505
71212402140
oct312157171
9120665085
1053010041
1127a17257
1215905135
13aca04b6
14707c757
1549c1a2b
hex328de79

53010041 has 4 divisors (see below), whose sum is σ = 60582912. Its totient is φ = 45437172.

The previous prime is 53009987. The next prime is 53010053. The reversal of 53010041 is 14001035.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 53010041 - 26 = 53009977 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 53009998 and 53010025.

It is not an unprimeable number, because it can be changed into a prime (53010071) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3786425 + ... + 3786438.

It is an arithmetic number, because the mean of its divisors is an integer number (15145728).

Almost surely, 253010041 is an apocalyptic number.

It is an amenable number.

53010041 is a deficient number, since it is larger than the sum of its proper divisors (7572871).

53010041 is an equidigital number, since it uses as much as digits as its factorization.

53010041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7572870.

The product of its (nonzero) digits is 60, while the sum is 14.

The square root of 53010041 is about 7280.7994753324. The cubic root of 53010041 is about 375.6522952231.

Adding to 53010041 its reverse (14001035), we get a palindrome (67011076).

The spelling of 53010041 in words is "fifty-three million, ten thousand, forty-one".

Divisors: 1 7 7572863 53010041