Base | Representation |
---|---|
bin | 1111011011011001110… |
… | …10101100100100010011 |
3 | 1212200022011022000021101 |
4 | 13231230322230210103 |
5 | 32141130211204020 |
6 | 1043310044405231 |
7 | 53204402143261 |
oct | 7555472544423 |
9 | 1780264260241 |
10 | 530108303635 |
11 | 1948aa354669 |
12 | 868a4246817 |
13 | 3acb1aa3061 |
14 | 1b92bbc1431 |
15 | dbc900200a |
hex | 7b6ceac913 |
530108303635 has 4 divisors (see below), whose sum is σ = 636129964368. Its totient is φ = 424086642904.
The previous prime is 530108303603. The next prime is 530108303639. The reversal of 530108303635 is 536303801035.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 536303801035 = 5 ⋅107260760207.
It is a cyclic number.
It is not a de Polignac number, because 530108303635 - 25 = 530108303603 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 530108303594 and 530108303603.
It is not an unprimeable number, because it can be changed into a prime (530108303639) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 53010830359 + ... + 53010830368.
It is an arithmetic number, because the mean of its divisors is an integer number (159032491092).
Almost surely, 2530108303635 is an apocalyptic number.
530108303635 is a deficient number, since it is larger than the sum of its proper divisors (106021660733).
530108303635 is a wasteful number, since it uses less digits than its factorization.
530108303635 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 106021660732.
The product of its (nonzero) digits is 97200, while the sum is 37.
The spelling of 530108303635 in words is "five hundred thirty billion, one hundred eight million, three hundred three thousand, six hundred thirty-five".
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