Base | Representation |
---|---|
bin | 110001010111101101… |
… | …110111100110010011 |
3 | 12001211110000111110011 |
4 | 301113231313212103 |
5 | 1332031334441210 |
6 | 40204131015351 |
7 | 3554445120655 |
oct | 612755674623 |
9 | 161743014404 |
10 | 53011249555 |
11 | 20533517450 |
12 | a33543a557 |
13 | 4cca8927b4 |
14 | 27cc6246d5 |
15 | 15a3e0bd8a |
hex | c57b77993 |
53011249555 has 8 divisors (see below), whose sum is σ = 69396544944. Its totient is φ = 38553636000.
The previous prime is 53011249553. The next prime is 53011249561. The reversal of 53011249555 is 55594211035.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 53011249555 - 21 = 53011249553 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (53011249553) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 481920396 + ... + 481920505.
It is an arithmetic number, because the mean of its divisors is an integer number (8674568118).
Almost surely, 253011249555 is an apocalyptic number.
53011249555 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
53011249555 is a deficient number, since it is larger than the sum of its proper divisors (16385295389).
53011249555 is a wasteful number, since it uses less digits than its factorization.
53011249555 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 963840917.
The product of its (nonzero) digits is 135000, while the sum is 40.
The spelling of 53011249555 in words is "fifty-three billion, eleven million, two hundred forty-nine thousand, five hundred fifty-five".
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