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530113153 = 811765309
BaseRepresentation
bin11111100110001…
…110001010000001
31100221111112112111
4133212032022001
52041202110103
6124334055321
716064613253
oct3746161201
91327445474
10530113153
11252264949
1212964a541
1385a9972b
1450593cd3
153181586d
hex1f98e281

530113153 has 4 divisors (see below), whose sum is σ = 530186580. Its totient is φ = 530039728.

The previous prime is 530113151. The next prime is 530113187. The reversal of 530113153 is 351311035.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 462594064 + 67519089 = 21508^2 + 8217^2 .

It is a cyclic number.

It is not a de Polignac number, because 530113153 - 21 = 530113151 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (530113151) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24538 + ... + 40771.

It is an arithmetic number, because the mean of its divisors is an integer number (132546645).

Almost surely, 2530113153 is an apocalyptic number.

It is an amenable number.

530113153 is a deficient number, since it is larger than the sum of its proper divisors (73427).

530113153 is an equidigital number, since it uses as much as digits as its factorization.

530113153 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 73426.

The product of its (nonzero) digits is 675, while the sum is 22.

The square root of 530113153 is about 23024.1862614078. The cubic root of 530113153 is about 809.3248211921.

Adding to 530113153 its reverse (351311035), we get a palindrome (881424188).

The spelling of 530113153 in words is "five hundred thirty million, one hundred thirteen thousand, one hundred fifty-three".

Divisors: 1 8117 65309 530113153