Base | Representation |
---|---|
bin | 1100101000111… |
… | …0011010110011 |
3 | 10200202021222212 |
4 | 3022032122303 |
5 | 102032342042 |
6 | 5132122335 |
7 | 1212411236 |
oct | 312163263 |
9 | 120667885 |
10 | 53012147 |
11 | 27a188a1 |
12 | 159063ab |
13 | aca1446 |
14 | 707d41d |
15 | 49c2482 |
hex | 328e6b3 |
53012147 has 4 divisors (see below), whose sum is σ = 55802280. Its totient is φ = 50222016.
The previous prime is 53012123. The next prime is 53012153. The reversal of 53012147 is 74121035.
It is a semiprime because it is the product of two primes.
It is a de Polignac number, because none of the positive numbers 2k-53012147 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (53012107) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1395038 + ... + 1395075.
It is an arithmetic number, because the mean of its divisors is an integer number (13950570).
Almost surely, 253012147 is an apocalyptic number.
53012147 is a deficient number, since it is larger than the sum of its proper divisors (2790133).
53012147 is a wasteful number, since it uses less digits than its factorization.
53012147 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2790132.
The product of its (nonzero) digits is 840, while the sum is 23.
The square root of 53012147 is about 7280.9441008704. The cubic root of 53012147 is about 375.6572698358.
The spelling of 53012147 in words is "fifty-three million, twelve thousand, one hundred forty-seven".
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