Base | Representation |
---|---|
bin | 1111011011011100001… |
… | …00110101101111111011 |
3 | 1212200100111212110211000 |
4 | 13231232010311233323 |
5 | 32141200200134044 |
6 | 1043312021140043 |
7 | 53205026303622 |
oct | 7555604655773 |
9 | 1780314773730 |
10 | 530127739899 |
11 | 19490a31a39a |
12 | 868aa85a623 |
13 | 3acb5b199c4 |
14 | 1b9306006b9 |
15 | dbcaa90d69 |
hex | 7b6e135bfb |
530127739899 has 16 divisors (see below), whose sum is σ = 785390192640. Its totient is φ = 353411399880.
The previous prime is 530127739853. The next prime is 530127739931. The reversal of 530127739899 is 998937721035.
530127739899 is a `hidden beast` number, since 5 + 30 + 127 + 7 + 398 + 99 = 666.
It is not a de Polignac number, because 530127739899 - 29 = 530127739387 is a prime.
It is a super-2 number, since 2×5301277398992 (a number of 24 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (530127739499) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1412014 + ... + 1747580.
It is an arithmetic number, because the mean of its divisors is an integer number (49086887040).
Almost surely, 2530127739899 is an apocalyptic number.
530127739899 is a deficient number, since it is larger than the sum of its proper divisors (255262452741).
530127739899 is a wasteful number, since it uses less digits than its factorization.
530127739899 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 394087 (or 394081 counting only the distinct ones).
The product of its (nonzero) digits is 25719120, while the sum is 63.
The spelling of 530127739899 in words is "five hundred thirty billion, one hundred twenty-seven million, seven hundred thirty-nine thousand, eight hundred ninety-nine".
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