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530127739899 = 3358511335567
BaseRepresentation
bin1111011011011100001…
…00110101101111111011
31212200100111212110211000
413231232010311233323
532141200200134044
61043312021140043
753205026303622
oct7555604655773
91780314773730
10530127739899
1119490a31a39a
12868aa85a623
133acb5b199c4
141b9306006b9
15dbcaa90d69
hex7b6e135bfb

530127739899 has 16 divisors (see below), whose sum is σ = 785390192640. Its totient is φ = 353411399880.

The previous prime is 530127739853. The next prime is 530127739931. The reversal of 530127739899 is 998937721035.

530127739899 is a `hidden beast` number, since 5 + 30 + 127 + 7 + 398 + 99 = 666.

It is not a de Polignac number, because 530127739899 - 29 = 530127739387 is a prime.

It is a super-2 number, since 2×5301277398992 (a number of 24 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (530127739499) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1412014 + ... + 1747580.

It is an arithmetic number, because the mean of its divisors is an integer number (49086887040).

Almost surely, 2530127739899 is an apocalyptic number.

530127739899 is a deficient number, since it is larger than the sum of its proper divisors (255262452741).

530127739899 is a wasteful number, since it uses less digits than its factorization.

530127739899 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 394087 (or 394081 counting only the distinct ones).

The product of its (nonzero) digits is 25719120, while the sum is 63.

The spelling of 530127739899 in words is "five hundred thirty billion, one hundred twenty-seven million, seven hundred thirty-nine thousand, eight hundred ninety-nine".

Divisors: 1 3 9 27 58511 175533 335567 526599 1006701 1579797 3020103 9060309 19634360737 58903082211 176709246633 530127739899