Base | Representation |
---|---|
bin | 100110100100100111001… |
… | …0101111111011100111011 |
3 | 200202210120222210210110001 |
4 | 1031021032111333130323 |
5 | 1143324032312443120 |
6 | 15135215131333431 |
7 | 1055002153524325 |
oct | 115111625773473 |
9 | 20683528723401 |
10 | 5301304031035 |
11 | 17642a7a14661 |
12 | 717517bb1277 |
13 | 2c5bac10c86c |
14 | 144827b78615 |
15 | 92d74619e0a |
hex | 4d24e57f73b |
5301304031035 has 16 divisors (see below), whose sum is σ = 6372250682112. Its totient is φ = 4233924547200.
The previous prime is 5301304031029. The next prime is 5301304031071.
5301304031035 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 5301304031035 - 27 = 5301304030907 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 5301304030994 and 5301304031012.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 7835670 + ... + 8485300.
It is an arithmetic number, because the mean of its divisors is an integer number (398265667632).
Almost surely, 25301304031035 is an apocalyptic number.
5301304031035 is a deficient number, since it is larger than the sum of its proper divisors (1070946651077).
5301304031035 is a wasteful number, since it uses less digits than its factorization.
5301304031035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 652374.
The product of its (nonzero) digits is 8100, while the sum is 28.
The spelling of 5301304031035 in words is "five trillion, three hundred one billion, three hundred four million, thirty-one thousand, thirty-five".
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