53013041154153 has 12 divisors (see below), whose sum is σ = 76605995943360. Its totient is φ = 35327441359896.

The previous prime is 53013041154149. The next prime is 53013041154191. The reversal of 53013041154153 is 35145114031035.

53013041154153 is a `hidden beast` number, since 5 + 30 + 1 + 30 + 4 + 1 + 1 + 541 + 53 = 666.

It is not a de Polignac number, because 53013041154153 - 2² = 53013041154149 is a prime.

It is not an unprimeable number, because it can be changed into a prime (53013041154053) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1215483333 + ... + 1215526946.

It is an arithmetic number, because the mean of its divisors is an integer number (6383832995280).

Almost surely, 2^{53013041154153} is an apocalyptic number.

It is an amenable number.

53013041154153 is a deficient number, since it is larger than the sum of its proper divisors (23592954789207).

53013041154153 is a wasteful number, since it uses less digits than its factorization.

53013041154153 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2431012708 (or 2431012705 counting only the distinct ones).

The product of its (nonzero) digits is 54000, while the sum is 36.

Adding to 53013041154153 its reverse (35145114031035), we get a palindrome (88158155185188).

The spelling of 53013041154153 in words is "fifty-three trillion, thirteen billion, forty-one million, one hundred fifty-four thousand, one hundred fifty-three".