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5301321001 = 7603697267
BaseRepresentation
bin1001110111111101…
…11011110100101001
3111200110101000021021
410323332323310221
541324114233001
62234013412441
7245241325234
oct47376736451
914613330237
105301321001
112280503a29
12103b49a121
136663cca42
143840da41b
15210626ba1
hex13bfbbd29

5301321001 has 4 divisors (see below), whose sum is σ = 5302025872. Its totient is φ = 5300616132.

The previous prime is 5301320993. The next prime is 5301321007. The reversal of 5301321001 is 1001231035.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 5301321001 - 23 = 5301320993 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (5301321007) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 341031 + ... + 356236.

It is an arithmetic number, because the mean of its divisors is an integer number (1325506468).

Almost surely, 25301321001 is an apocalyptic number.

It is an amenable number.

5301321001 is a deficient number, since it is larger than the sum of its proper divisors (704871).

5301321001 is an equidigital number, since it uses as much as digits as its factorization.

5301321001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 704870.

The product of its (nonzero) digits is 90, while the sum is 16.

The square root of 5301321001 is about 72810.1709996619. The cubic root of 5301321001 is about 1743.6582435054.

Adding to 5301321001 its reverse (1001231035), we get a palindrome (6302552036).

The spelling of 5301321001 in words is "five billion, three hundred one million, three hundred twenty-one thousand, one".

Divisors: 1 7603 697267 5301321001