Base | Representation |
---|---|
bin | 110001010111110110… |
… | …001110011001101001 |
3 | 12001211121010210022122 |
4 | 301113312032121221 |
5 | 1332032420040410 |
6 | 40204250001025 |
7 | 3554502543263 |
oct | 612766163151 |
9 | 161747123278 |
10 | 53013440105 |
11 | 2053478321a |
12 | a336116175 |
13 | 4ccb17b892 |
14 | 27cca34b33 |
15 | 15a41e0e55 |
hex | c57d8e669 |
53013440105 has 4 divisors (see below), whose sum is σ = 63616128132. Its totient is φ = 42410752080.
The previous prime is 53013440099. The next prime is 53013440131. The reversal of 53013440105 is 50104431035.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 10957274329 + 42056165776 = 104677^2 + 205076^2 .
It is not a de Polignac number, because 53013440105 - 28 = 53013439849 is a prime.
It is a super-2 number, since 2×530134401052 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5301344006 + ... + 5301344015.
It is an arithmetic number, because the mean of its divisors is an integer number (15904032033).
Almost surely, 253013440105 is an apocalyptic number.
It is an amenable number.
53013440105 is a deficient number, since it is larger than the sum of its proper divisors (10602688027).
53013440105 is a wasteful number, since it uses less digits than its factorization.
53013440105 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10602688026.
The product of its (nonzero) digits is 3600, while the sum is 26.
The spelling of 53013440105 in words is "fifty-three billion, thirteen million, four hundred forty thousand, one hundred five".
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