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5301401131 = 13407800087
BaseRepresentation
bin1001110111111110…
…01111011000101011
3111200110112002012001
410323333033120223
541324124314011
62234015231431
7245242110655
oct47377173053
914613462161
105301401131
112280559154
12103b518577
1366642a360
1438411b6d5
152106407c1
hex13bfcf62b

5301401131 has 4 divisors (see below), whose sum is σ = 5709201232. Its totient is φ = 4893601032.

The previous prime is 5301401113. The next prime is 5301401137. The reversal of 5301401131 is 1311041035.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 5301401131 - 27 = 5301401003 is a prime.

It is a super-2 number, since 2×53014011312 = 56209707903536158322, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 5301401099 and 5301401108.

It is not an unprimeable number, because it can be changed into a prime (5301401137) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 203900031 + ... + 203900056.

It is an arithmetic number, because the mean of its divisors is an integer number (1427300308).

Almost surely, 25301401131 is an apocalyptic number.

5301401131 is a deficient number, since it is larger than the sum of its proper divisors (407800101).

5301401131 is a wasteful number, since it uses less digits than its factorization.

5301401131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 407800100.

The product of its (nonzero) digits is 180, while the sum is 19.

The square root of 5301401131 is about 72810.7212641105. The cubic root of 5301401131 is about 1743.6670286510.

Adding to 5301401131 its reverse (1311041035), we get a palindrome (6612442166).

The spelling of 5301401131 in words is "five billion, three hundred one million, four hundred one thousand, one hundred thirty-one".

Divisors: 1 13 407800087 5301401131