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530140403 = 13371102163
BaseRepresentation
bin11111100110010…
…100110011110011
31100221112220220202
4133212110303303
52041203443103
6124334425415
716065055562
oct3746246363
91327486822
10530140403
11252283371
1212966226b
1385aa8c60
145059dbd9
153181d988
hex1f994cf3

530140403 has 8 divisors (see below), whose sum is σ = 586351248. Its totient is φ = 476133984.

The previous prime is 530140379. The next prime is 530140433. The reversal of 530140403 is 304041035.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-530140403 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (530140433) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 550601 + ... + 551562.

It is an arithmetic number, because the mean of its divisors is an integer number (73293906).

Almost surely, 2530140403 is an apocalyptic number.

530140403 is a deficient number, since it is larger than the sum of its proper divisors (56210845).

530140403 is a wasteful number, since it uses less digits than its factorization.

530140403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1102213.

The product of its (nonzero) digits is 720, while the sum is 20.

The square root of 530140403 is about 23024.7780228171. The cubic root of 530140403 is about 809.3386884978.

Adding to 530140403 its reverse (304041035), we get a palindrome (834181438).

The spelling of 530140403 in words is "five hundred thirty million, one hundred forty thousand, four hundred three".

Divisors: 1 13 37 481 1102163 14328119 40780031 530140403