Base | Representation |
---|---|
bin | 100110100100101010011… |
… | …1010110000001010000011 |
3 | 200202210212200100121120100 |
4 | 1031021110322300022003 |
5 | 1143324244032043021 |
6 | 15135234111413443 |
7 | 1055004663205521 |
oct | 115112472601203 |
9 | 20683780317510 |
10 | 5301414331011 |
11 | 1764354200667 |
12 | 717548b24283 |
13 | 2c5bc8c1b616 |
14 | 14483868b311 |
15 | 92d7e156626 |
hex | 4d254eb0283 |
5301414331011 has 6 divisors (see below), whose sum is σ = 7657598478140. Its totient is φ = 3534276220668.
The previous prime is 5301414330881. The next prime is 5301414331019. The reversal of 5301414331011 is 1101334141035.
5301414331011 is a `hidden beast` number, since 5 + 301 + 4 + 1 + 43 + 310 + 1 + 1 = 666.
It is not a de Polignac number, because 5301414331011 - 211 = 5301414328963 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5301414331019) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 294523018381 + ... + 294523018398.
Almost surely, 25301414331011 is an apocalyptic number.
5301414331011 is a deficient number, since it is larger than the sum of its proper divisors (2356184147129).
5301414331011 is a wasteful number, since it uses less digits than its factorization.
5301414331011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 589046036785 (or 589046036782 counting only the distinct ones).
The product of its (nonzero) digits is 2160, while the sum is 27.
Adding to 5301414331011 its reverse (1101334141035), we get a palindrome (6402748472046).
The spelling of 5301414331011 in words is "five trillion, three hundred one billion, four hundred fourteen million, three hundred thirty-one thousand, eleven".
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