Base | Representation |
---|---|
bin | 111100010001010010010110… |
… | …1001000010100110001011001 |
3 | 2120112002000202112120110210011 |
4 | 1320202210231020110301121 |
5 | 1023441314200040412441 |
6 | 5115303342241121521 |
7 | 216444312321552121 |
oct | 17042445510246131 |
9 | 2515060675513704 |
10 | 530141455404121 |
11 | 143a128018a8690 |
12 | 4b560b709292a1 |
13 | 199a71810717a2 |
14 | 94cadaa449c81 |
15 | 41452e1084581 |
hex | 1e2292d214c59 |
530141455404121 has 8 divisors (see below), whose sum is σ = 578817678672288. Its totient is φ = 481545489720000.
The previous prime is 530141455404031. The next prime is 530141455404139. The reversal of 530141455404121 is 121404554141035.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 530141455404121 - 231 = 530139307920473 is a prime.
It is not an unprimeable number, because it can be changed into a prime (530141455404151) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 20064382195 + ... + 20064408616.
It is an arithmetic number, because the mean of its divisors is an integer number (72352209834036).
Almost surely, 2530141455404121 is an apocalyptic number.
It is an amenable number.
530141455404121 is a deficient number, since it is larger than the sum of its proper divisors (48676223268167).
530141455404121 is a wasteful number, since it uses less digits than its factorization.
530141455404121 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 40128792023.
The product of its (nonzero) digits is 192000, while the sum is 40.
The spelling of 530141455404121 in words is "five hundred thirty trillion, one hundred forty-one billion, four hundred fifty-five million, four hundred four thousand, one hundred twenty-one".
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