Base | Representation |
---|---|
bin | 110001010111111101… |
… | …110101011110001001 |
3 | 12001211201220011000000 |
4 | 301113331311132021 |
5 | 1332033422411040 |
6 | 40204400433213 |
7 | 3554525522601 |
oct | 612775653611 |
9 | 161751804000 |
10 | 53015435145 |
11 | 20535916112 |
12 | a336918809 |
13 | 4ccb6c998a |
14 | 27ccdd3c01 |
15 | 15a4487130 |
hex | c57f75789 |
53015435145 has 28 divisors (see below), whose sum is σ = 95384155716. Its totient is φ = 28274896800.
The previous prime is 53015435141. The next prime is 53015435173. The reversal of 53015435145 is 54153451035.
53015435145 is a `hidden beast` number, since 530 + 1 + 54 + 35 + 1 + 45 = 666.
It can be written as a sum of positive squares in 2 ways, for example, as 16048835856 + 36966599289 = 126684^2 + 192267^2 .
It is not a de Polignac number, because 53015435145 - 22 = 53015435141 is a prime.
It is a super-2 number, since 2×530154351452 (a number of 22 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (53015435141) by changing a digit.
It is a polite number, since it can be written in 27 ways as a sum of consecutive naturals, for example, 7268706 + ... + 7275995.
Almost surely, 253015435145 is an apocalyptic number.
It is an amenable number.
53015435145 is a deficient number, since it is larger than the sum of its proper divisors (42368720571).
53015435145 is an equidigital number, since it uses as much as digits as its factorization.
53015435145 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 14544724 (or 14544709 counting only the distinct ones).
The product of its (nonzero) digits is 90000, while the sum is 36.
The spelling of 53015435145 in words is "fifty-three billion, fifteen million, four hundred thirty-five thousand, one hundred forty-five".
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