Base | Representation |
---|---|
bin | 110001010111111110… |
… | …000101110011011001 |
3 | 12001211202000112202122 |
4 | 301113332011303121 |
5 | 1332033432031131 |
6 | 40204402111025 |
7 | 3554526221615 |
oct | 612776056331 |
9 | 161752015678 |
10 | 53015502041 |
11 | 205359613a7 |
12 | a33694b475 |
13 | 4ccb721268 |
14 | 27cd010345 |
15 | 15a449bd7b |
hex | c57f85cd9 |
53015502041 has 4 divisors (see below), whose sum is σ = 53017650432. Its totient is φ = 53013353652.
The previous prime is 53015502037. The next prime is 53015502073. The reversal of 53015502041 is 14020551035.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 53015502041 - 22 = 53015502037 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is a self number, because there is not a number n which added to its sum of digits gives 53015502041.
It is not an unprimeable number, because it can be changed into a prime (53015502641) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1036745 + ... + 1086678.
It is an arithmetic number, because the mean of its divisors is an integer number (13254412608).
Almost surely, 253015502041 is an apocalyptic number.
It is an amenable number.
53015502041 is a deficient number, since it is larger than the sum of its proper divisors (2148391).
53015502041 is a wasteful number, since it uses less digits than its factorization.
53015502041 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2148390.
The product of its (nonzero) digits is 3000, while the sum is 26.
The spelling of 53015502041 in words is "fifty-three billion, fifteen million, five hundred two thousand, forty-one".
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