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5302003 = 7757429
BaseRepresentation
bin10100001110011011110011
3100222100222111
4110032123303
52324131003
6305350151
763031510
oct24163363
910870874
105302003
112aa1523
121938357
1311383a5
149c0307
156eae6d
hex50e6f3

5302003 has 4 divisors (see below), whose sum is σ = 6059440. Its totient is φ = 4544568.

The previous prime is 5302001. The next prime is 5302009. The reversal of 5302003 is 3002035.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 3002035 = 5600407.

It is not a de Polignac number, because 5302003 - 21 = 5302001 is a prime.

It is a super-2 number, since 2×53020032 = 56222471624018, which contains 22 as substring.

It is a Duffinian number.

5302003 is a lucky number.

It is not an unprimeable number, because it can be changed into a prime (5302001) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 378708 + ... + 378721.

It is an arithmetic number, because the mean of its divisors is an integer number (1514860).

Almost surely, 25302003 is an apocalyptic number.

5302003 is a deficient number, since it is larger than the sum of its proper divisors (757437).

5302003 is an equidigital number, since it uses as much as digits as its factorization.

5302003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 757436.

The product of its (nonzero) digits is 90, while the sum is 13.

The square root of 5302003 is about 2302.6078693516. The cubic root of 5302003 is about 174.3733012429.

Adding to 5302003 its reverse (3002035), we get a palindrome (8304038).

Subtracting from 5302003 its reverse (3002035), we obtain a cube (2299968 = 1323).

The spelling of 5302003 in words is "five million, three hundred two thousand, three".

Divisors: 1 7 757429 5302003