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53021131 = 330716033
BaseRepresentation
bin1100101001000…
…0100111001011
310200202202022121
43022100213023
5102033134011
65132232111
71212446362
oct312204713
9120682277
1053021131
1127a24619
121590b637
13aca5567
1470827d9
1549c4e71
hex32909cb

53021131 has 4 divisors (see below), whose sum is σ = 53040472. Its totient is φ = 53001792.

The previous prime is 53021119. The next prime is 53021173. The reversal of 53021131 is 13112035.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 13112035 = 52622407.

It is a cyclic number.

It is not a de Polignac number, because 53021131 - 29 = 53020619 is a prime.

It is a super-2 number, since 2×530211312 = 5622480665038322, which contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (53021231) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4710 + ... + 11323.

It is an arithmetic number, because the mean of its divisors is an integer number (13260118).

Almost surely, 253021131 is an apocalyptic number.

53021131 is a deficient number, since it is larger than the sum of its proper divisors (19341).

53021131 is a wasteful number, since it uses less digits than its factorization.

53021131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 19340.

The product of its (nonzero) digits is 90, while the sum is 16.

The square root of 53021131 is about 7281.5610276918. The cubic root of 53021131 is about 375.6784895906.

Adding to 53021131 its reverse (13112035), we get a palindrome (66133166).

The spelling of 53021131 in words is "fifty-three million, twenty-one thousand, one hundred thirty-one".

Divisors: 1 3307 16033 53021131