Base | Representation |
---|---|
bin | 1111011011100110010… |
… | …11010001011000100011 |
3 | 1212200120110212222201101 |
4 | 13231303023101120203 |
5 | 32141334101441120 |
6 | 1043324315215231 |
7 | 53210115535231 |
oct | 7556313213043 |
9 | 1780513788641 |
10 | 530213312035 |
11 | 194953656a70 |
12 | 86913447517 |
13 | 3acca77b3c4 |
14 | 1b93bb17951 |
15 | dbd334590a |
hex | 7b732d1623 |
530213312035 has 16 divisors (see below), whose sum is σ = 734926688352. Its totient is φ = 362926758400.
The previous prime is 530213312023. The next prime is 530213312039.
530213312035 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 530213312035 - 211 = 530213309987 is a prime.
It is a super-2 number, since 2×5302133120352 (a number of 24 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 530213311994 and 530213312012.
It is not an unprimeable number, because it can be changed into a prime (530213312039) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 283535596 + ... + 283537465.
It is an arithmetic number, because the mean of its divisors is an integer number (45932918022).
Almost surely, 2530213312035 is an apocalyptic number.
530213312035 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
530213312035 is a deficient number, since it is larger than the sum of its proper divisors (204713376317).
530213312035 is a wasteful number, since it uses less digits than its factorization.
530213312035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 567073094.
The product of its (nonzero) digits is 8100, while the sum is 28.
It can be divided in two parts, 530213 and 312035, that added together give a palindrome (842248).
The spelling of 530213312035 in words is "five hundred thirty billion, two hundred thirteen million, three hundred twelve thousand, thirty-five".
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