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53021433 = 3732391013
BaseRepresentation
bin1100101001000…
…0101011111001
310200202202201210
43022100223321
5102033141213
65132233333
71212450303
oct312205371
9120682653
1053021433
1127a24873
121590b849
13aca573a
147082973
1549c50c3
hex3290af9

53021433 has 16 divisors (see below), whose sum is σ = 72034560. Its totient is φ = 34683264.

The previous prime is 53021431. The next prime is 53021447. The reversal of 53021433 is 33412035.

53021433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 53021433 - 21 = 53021431 is a prime.

It is a super-2 number, since 2×530214332 = 5622544714746978, which contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (53021431) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 51835 + ... + 52847.

It is an arithmetic number, because the mean of its divisors is an integer number (4502160).

Almost surely, 253021433 is an apocalyptic number.

It is an amenable number.

53021433 is a deficient number, since it is larger than the sum of its proper divisors (19013127).

53021433 is a wasteful number, since it uses less digits than its factorization.

53021433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1328.

The product of its (nonzero) digits is 1080, while the sum is 21.

The square root of 53021433 is about 7281.5817649739. The cubic root of 53021433 is about 375.6792028577.

Adding to 53021433 its reverse (33412035), we get a palindrome (86433468).

The spelling of 53021433 in words is "fifty-three million, twenty-one thousand, four hundred thirty-three".

Divisors: 1 3 73 219 239 717 1013 3039 17447 52341 73949 221847 242107 726321 17673811 53021433