Base | Representation |
---|---|
bin | 11000000111001101110111… |
… | …11000011101111110010001 |
3 | 20221202002120012112220200020 |
4 | 30003212323320131332101 |
5 | 23422223210443130340 |
6 | 304435044010414053 |
7 | 14111616056300253 |
oct | 1403467370357621 |
9 | 227662505486606 |
10 | 53024523411345 |
11 | 15993635134772 |
12 | 5b44611731329 |
13 | 2378263b10365 |
14 | d14587467cd3 |
15 | 61e4522d49d0 |
hex | 3039bbe1df91 |
53024523411345 has 8 divisors (see below), whose sum is σ = 84839237458176. Its totient is φ = 28279745819376.
The previous prime is 53024523411263. The next prime is 53024523411373. The reversal of 53024523411345 is 54311432542035.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 53024523411345 - 27 = 53024523411217 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 53024523411297 and 53024523411306.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1767484113697 + ... + 1767484113726.
It is an arithmetic number, because the mean of its divisors is an integer number (10604904682272).
Almost surely, 253024523411345 is an apocalyptic number.
It is an amenable number.
53024523411345 is a deficient number, since it is larger than the sum of its proper divisors (31814714046831).
53024523411345 is a wasteful number, since it uses less digits than its factorization.
53024523411345 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3534968227431.
The product of its (nonzero) digits is 864000, while the sum is 42.
The spelling of 53024523411345 in words is "fifty-three trillion, twenty-four billion, five hundred twenty-three million, four hundred eleven thousand, three hundred forty-five".
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