Base | Representation |
---|---|
bin | 110001011000100010… |
… | …110111101001000001 |
3 | 12001212102011101011120 |
4 | 301120202313221001 |
5 | 1332043414041421 |
6 | 40205344502453 |
7 | 3555004165461 |
oct | 613042675101 |
9 | 161772141146 |
10 | 53025143361 |
11 | 20540347033 |
12 | a33a01aa29 |
13 | 5000718798 |
14 | 27d03ddba1 |
15 | 15a52538c6 |
hex | c588b7a41 |
53025143361 has 8 divisors (see below), whose sum is σ = 74421253920. Its totient is φ = 33489564192.
The previous prime is 53025143341. The next prime is 53025143389. The reversal of 53025143361 is 16334152035.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 53025143361 - 210 = 53025142337 is a prime.
It is not an unprimeable number, because it can be changed into a prime (53025143321) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 465132780 + ... + 465132893.
It is an arithmetic number, because the mean of its divisors is an integer number (9302656740).
Almost surely, 253025143361 is an apocalyptic number.
It is an amenable number.
53025143361 is a deficient number, since it is larger than the sum of its proper divisors (21396110559).
53025143361 is a wasteful number, since it uses less digits than its factorization.
53025143361 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 930265695.
The product of its (nonzero) digits is 32400, while the sum is 33.
Adding to 53025143361 its reverse (16334152035), we get a palindrome (69359295396).
The spelling of 53025143361 in words is "fifty-three billion, twenty-five million, one hundred forty-three thousand, three hundred sixty-one".
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