Base | Representation |
---|---|
bin | 100110100101001100000… |
… | …0010111010100111000011 |
3 | 200202220210011112011222020 |
4 | 1031022120002322213003 |
5 | 1143334100334410301 |
6 | 15135541542212523 |
7 | 1055044616646603 |
oct | 115123002724703 |
9 | 20686704464866 |
10 | 5302540544451 |
11 | 176488199a477 |
12 | 717802124143 |
13 | 2c60483498c7 |
14 | 144904090c03 |
15 | 92de7e69436 |
hex | 4d2980ba9c3 |
5302540544451 has 4 divisors (see below), whose sum is σ = 7070054059272. Its totient is φ = 3535027029632.
The previous prime is 5302540544447. The next prime is 5302540544501. The reversal of 5302540544451 is 1544450452035.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 5302540544451 - 22 = 5302540544447 is a prime.
It is not an unprimeable number, because it can be changed into a prime (5302540544551) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 883756757406 + ... + 883756757411.
It is an arithmetic number, because the mean of its divisors is an integer number (1767513514818).
Almost surely, 25302540544451 is an apocalyptic number.
5302540544451 is a deficient number, since it is larger than the sum of its proper divisors (1767513514821).
5302540544451 is a wasteful number, since it uses less digits than its factorization.
5302540544451 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1767513514820.
The product of its (nonzero) digits is 960000, while the sum is 42.
Adding to 5302540544451 its reverse (1544450452035), we get a palindrome (6846990996486).
The spelling of 5302540544451 in words is "five trillion, three hundred two billion, five hundred forty million, five hundred forty-four thousand, four hundred fifty-one".
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