Base | Representation |
---|---|
bin | 100110100101001100000… |
… | …0010111100100100000011 |
3 | 200202220210011112120221112 |
4 | 1031022120002330210003 |
5 | 1143334100340134301 |
6 | 15135541542313535 |
7 | 1055044620012122 |
oct | 115123002744403 |
9 | 20686704476845 |
10 | 5302540552451 |
11 | 17648819a548a |
12 | 7178021288ab |
13 | 2c604835043c |
14 | 144904093ab9 |
15 | 92de7e6b9bb |
hex | 4d2980bc903 |
5302540552451 has 12 divisors (see below), whose sum is σ = 5473524006720. Its totient is φ = 5136698959200.
The previous prime is 5302540552447. The next prime is 5302540552481. The reversal of 5302540552451 is 1542550452035.
It is not a de Polignac number, because 5302540552451 - 22 = 5302540552447 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 5302540552399 and 5302540552408.
It is not an unprimeable number, because it can be changed into a prime (5302540552481) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 8143475 + ... + 8770476.
It is an arithmetic number, because the mean of its divisors is an integer number (456127000560).
Almost surely, 25302540552451 is an apocalyptic number.
5302540552451 is a deficient number, since it is larger than the sum of its proper divisors (170983454269).
5302540552451 is a wasteful number, since it uses less digits than its factorization.
5302540552451 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 16914254 (or 16914217 counting only the distinct ones).
The product of its (nonzero) digits is 600000, while the sum is 41.
The spelling of 5302540552451 in words is "five trillion, three hundred two billion, five hundred forty million, five hundred fifty-two thousand, four hundred fifty-one".
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