Base | Representation |
---|---|
bin | 100110100101001100000… |
… | …1010011011000011011001 |
3 | 200202220210022020011102012 |
4 | 1031022120022123003121 |
5 | 1143334101340343340 |
6 | 15135542052315305 |
7 | 1055044642454111 |
oct | 115123012330331 |
9 | 20686708204365 |
10 | 5302542512345 |
11 | 1764883013a31 |
12 | 717802912b35 |
13 | 2c6048888540 |
14 | 144904444041 |
15 | 92de8207565 |
hex | 4d29829b0d9 |
5302542512345 has 16 divisors (see below), whose sum is σ = 6853994658000. Its totient is φ = 3914879026944.
The previous prime is 5302542512303. The next prime is 5302542512381. The reversal of 5302542512345 is 5432152452035.
It can be written as a sum of positive squares in 8 ways, for example, as 2458840388761 + 2843702123584 = 1568069^2 + 1686328^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5302542512345 is a prime.
It is a Curzon number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 8494970 + ... + 9097779.
It is an arithmetic number, because the mean of its divisors is an integer number (428374666125).
Almost surely, 25302542512345 is an apocalyptic number.
It is an amenable number.
5302542512345 is a deficient number, since it is larger than the sum of its proper divisors (1551452145655).
5302542512345 is a wasteful number, since it uses less digits than its factorization.
5302542512345 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 17597404.
The product of its (nonzero) digits is 720000, while the sum is 41.
The spelling of 5302542512345 in words is "five trillion, three hundred two billion, five hundred forty-two million, five hundred twelve thousand, three hundred forty-five".
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