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5302542512345 = 513463717592749
BaseRepresentation
bin100110100101001100000…
…1010011011000011011001
3200202220210022020011102012
41031022120022123003121
51143334101340343340
615135542052315305
71055044642454111
oct115123012330331
920686708204365
105302542512345
111764883013a31
12717802912b35
132c6048888540
14144904444041
1592de8207565
hex4d29829b0d9

5302542512345 has 16 divisors (see below), whose sum is σ = 6853994658000. Its totient is φ = 3914879026944.

The previous prime is 5302542512303. The next prime is 5302542512381. The reversal of 5302542512345 is 5432152452035.

It can be written as a sum of positive squares in 8 ways, for example, as 2458840388761 + 2843702123584 = 1568069^2 + 1686328^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5302542512345 is a prime.

It is a Curzon number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 8494970 + ... + 9097779.

It is an arithmetic number, because the mean of its divisors is an integer number (428374666125).

Almost surely, 25302542512345 is an apocalyptic number.

It is an amenable number.

5302542512345 is a deficient number, since it is larger than the sum of its proper divisors (1551452145655).

5302542512345 is a wasteful number, since it uses less digits than its factorization.

5302542512345 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 17597404.

The product of its (nonzero) digits is 720000, while the sum is 41.

The spelling of 5302542512345 in words is "five trillion, three hundred two billion, five hundred forty-two million, five hundred twelve thousand, three hundred forty-five".

Divisors: 1 5 13 65 4637 23185 60281 301405 17592749 87963745 228705737 1143528685 81577577113 407887885565 1060508502469 5302542512345