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530254440635 = 5106050888127
BaseRepresentation
bin1111011011101011010…
…00001010100010111011
31212200200100021112112212
413231311220022202323
532141430114100020
61043332344525335
753211125243543
oct7556550124273
91780610245485
10530254440635
11194974898547
128692518084b
133b00614b85a
141b943382323
15dbd6c6bcc5
hex7b75a0a8bb

530254440635 has 4 divisors (see below), whose sum is σ = 636305328768. Its totient is φ = 424203552504.

The previous prime is 530254440619. The next prime is 530254440647. The reversal of 530254440635 is 536044452035.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 536044452035 = 5107208890407.

It is a cyclic number.

It is not a de Polignac number, because 530254440635 - 24 = 530254440619 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 530254440592 and 530254440601.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 53025444059 + ... + 53025444068.

It is an arithmetic number, because the mean of its divisors is an integer number (159076332192).

Almost surely, 2530254440635 is an apocalyptic number.

530254440635 is a deficient number, since it is larger than the sum of its proper divisors (106050888133).

530254440635 is a wasteful number, since it uses less digits than its factorization.

530254440635 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 106050888132.

The product of its (nonzero) digits is 864000, while the sum is 41.

The spelling of 530254440635 in words is "five hundred thirty billion, two hundred fifty-four million, four hundred forty thousand, six hundred thirty-five".

Divisors: 1 5 106050888127 530254440635