Base | Representation |
---|---|
bin | 110001011000110101… |
… | …100000000111101001 |
3 | 12001212202100112021222 |
4 | 301120311200013221 |
5 | 1332101141342003 |
6 | 40210041311425 |
7 | 3555063540623 |
oct | 613065400751 |
9 | 161782315258 |
10 | 53030027753 |
11 | 2054308281a |
12 | a33b795575 |
13 | 5001738a61 |
14 | 27d0d11c13 |
15 | 15a58bac38 |
hex | c58d601e9 |
53030027753 has 4 divisors (see below), whose sum is σ = 53499320148. Its totient is φ = 52560735360.
The previous prime is 53030027707. The next prime is 53030027759. The reversal of 53030027753 is 35772003035.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 4818164569 + 48211863184 = 69413^2 + 219572^2 .
It is a cyclic number.
It is not a de Polignac number, because 53030027753 - 28 = 53030027497 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (53030027759) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 234646028 + ... + 234646253.
It is an arithmetic number, because the mean of its divisors is an integer number (13374830037).
Almost surely, 253030027753 is an apocalyptic number.
It is an amenable number.
53030027753 is a deficient number, since it is larger than the sum of its proper divisors (469292395).
53030027753 is a wasteful number, since it uses less digits than its factorization.
53030027753 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 469292394.
The product of its (nonzero) digits is 66150, while the sum is 35.
The spelling of 53030027753 in words is "fifty-three billion, thirty million, twenty-seven thousand, seven hundred fifty-three".
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