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5303053052803 = 111613298881421
BaseRepresentation
bin100110100101011011010…
…0101111110101110000011
3200202222002212220022021001
41031022312211332232003
51143341123040142203
615140104451112431
71055063412131212
oct115126645765603
920688085808231
105303053052803
11176501521a5a0
127179258a2717
132c60ca59119c
14144952181079
1592e27e5391d
hex4d2b697eb83

5303053052803 has 8 divisors (see below), whose sum is σ = 5788735381296. Its totient is φ = 4817968490400.

The previous prime is 5303053052777. The next prime is 5303053052833. The reversal of 5303053052803 is 3082503503035.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 5303053052803 - 221 = 5303050955651 is a prime.

It is a super-3 number, since 3×53030530528033 (a number of 39 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (5303053052833) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 149422968 + ... + 149458453.

It is an arithmetic number, because the mean of its divisors is an integer number (723591922662).

Almost surely, 25303053052803 is an apocalyptic number.

5303053052803 is a deficient number, since it is larger than the sum of its proper divisors (485682328493).

5303053052803 is a wasteful number, since it uses less digits than its factorization.

5303053052803 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 298883045.

The product of its (nonzero) digits is 162000, while the sum is 37.

Adding to 5303053052803 its reverse (3082503503035), we get a palindrome (8385556555838).

The spelling of 5303053052803 in words is "five trillion, three hundred three billion, fifty-three million, fifty-two thousand, eight hundred three".

Divisors: 1 11 1613 17743 298881421 3287695631 482095732073 5303053052803