53031115 has 4 divisors (see below), whose sum is σ = 63637344. Its totient is φ = 42424888.

The previous prime is 53031113. The next prime is 53031127. The reversal of 53031115 is 51113035.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 51113035 = 5 ⋅10222607.

It is a cyclic number.

It is not a de Polignac number, because 53031115 - 2¹ = 53031113 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 53031092 and 53031101.

It is not an unprimeable number, because it can be changed into a prime (53031113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5303107 + ... + 5303116.

It is an arithmetic number, because the mean of its divisors is an integer number (15909336).

Almost surely, 2^53031115 is an apocalyptic number.

53031115 is a deficient number, since it is larger than the sum of its proper divisors (10606229).

53031115 is a wasteful number, since it uses less digits than its factorization.

53031115 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10606228.

The product of its (nonzero) digits is 225, while the sum is 19.

The square root of 53031115 is about 7282.2465627030. The cubic root of 53031115 is about 375.7020684830.

The spelling of 53031115 in words is "fifty-three million, thirty-one thousand, one hundred fifteen".