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530314241 = 3117106911
BaseRepresentation
bin11111100110111…
…111010000000001
31100221212202101012
4133212333100001
52041230023431
6124342250305
716066411442
oct3746772001
91327782335
10530314241
11252391a36
12129726995
1385b3a112
14506072c9
153185522b
hex1f9bf401

530314241 has 4 divisors (see below), whose sum is σ = 547421184. Its totient is φ = 513207300.

The previous prime is 530314231. The next prime is 530314249. The reversal of 530314241 is 142413035.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 142413035 = 528482607.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-530314241 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (530314249) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8553425 + ... + 8553486.

It is an arithmetic number, because the mean of its divisors is an integer number (136855296).

Almost surely, 2530314241 is an apocalyptic number.

It is an amenable number.

530314241 is a deficient number, since it is larger than the sum of its proper divisors (17106943).

530314241 is a wasteful number, since it uses less digits than its factorization.

530314241 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 17106942.

The product of its (nonzero) digits is 1440, while the sum is 23.

The square root of 530314241 is about 23028.5527335089. The cubic root of 530314241 is about 809.4271420739.

Adding to 530314241 its reverse (142413035), we get a palindrome (672727276).

The spelling of 530314241 in words is "five hundred thirty million, three hundred fourteen thousand, two hundred forty-one".

Divisors: 1 31 17106911 530314241