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53032335041 = 77576047863
BaseRepresentation
bin110001011000111110…
…010011011011000001
312001212220200202022002
4301120332103123001
51332102234210131
640210202553345
73555122260460
oct613076233301
9161786622262
1053032335041
1120544409274
12a340508855
13500206600a
1427d13529d7
1515a5bc46cb
hexc58f936c1

53032335041 has 4 divisors (see below), whose sum is σ = 60608382912. Its totient is φ = 45456287172.

The previous prime is 53032335011. The next prime is 53032335047. The reversal of 53032335041 is 14053323035.

53032335041 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 53032335041 - 26 = 53032334977 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 53032334995 and 53032335013.

It is not an unprimeable number, because it can be changed into a prime (53032335047) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3788023925 + ... + 3788023938.

It is an arithmetic number, because the mean of its divisors is an integer number (15152095728).

Almost surely, 253032335041 is an apocalyptic number.

It is an amenable number.

53032335041 is a deficient number, since it is larger than the sum of its proper divisors (7576047871).

53032335041 is an equidigital number, since it uses as much as digits as its factorization.

53032335041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7576047870.

The product of its (nonzero) digits is 16200, while the sum is 29.

Adding to 53032335041 its reverse (14053323035), we get a palindrome (67085658076).

The spelling of 53032335041 in words is "fifty-three billion, thirty-two million, three hundred thirty-five thousand, forty-one".

Divisors: 1 7 7576047863 53032335041