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53032421241 = 325892491249
BaseRepresentation
bin110001011000111110…
…101000011101111001
312001212220212010112200
4301120332220131321
51332102244434431
640210204500413
73555123100002
oct613076503571
9161786763480
1053032421241
1120544468008
12a34054a709
135002096317
1427d13761a9
1515a5bdeee6
hexc58fa8779

53032421241 has 6 divisors (see below), whose sum is σ = 76602386250. Its totient is φ = 35354947488.

The previous prime is 53032421231. The next prime is 53032421243. The reversal of 53032421241 is 14212423035.

53032421241 is a `hidden beast` number, since 530 + 3 + 2 + 4 + 2 + 124 + 1 = 666.

It can be written as a sum of positive squares in only one way, i.e., 42344996841 + 10687424400 = 205779^2 + 103380^2 .

It is not a de Polignac number, because 53032421241 - 218 = 53032159097 is a prime.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (53032421243) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 2946245616 + ... + 2946245633.

It is an arithmetic number, because the mean of its divisors is an integer number (12767064375).

Almost surely, 253032421241 is an apocalyptic number.

It is an amenable number.

53032421241 is a deficient number, since it is larger than the sum of its proper divisors (23569965009).

53032421241 is a wasteful number, since it uses less digits than its factorization.

53032421241 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5892491255 (or 5892491252 counting only the distinct ones).

The product of its (nonzero) digits is 5760, while the sum is 27.

Adding to 53032421241 its reverse (14212423035), we get a palindrome (67244844276).

The spelling of 53032421241 in words is "fifty-three billion, thirty-two million, four hundred twenty-one thousand, two hundred forty-one".

Divisors: 1 3 9 5892491249 17677473747 53032421241