53032535433 has 8 divisors (see below), whose sum is σ = 78566719200. Its totient is φ = 35355023604.

The previous prime is 53032535429. The next prime is 53032535459. The reversal of 53032535433 is 33453523035.

53032535433 is a `hidden beast` number, since 5 + 30 + 32 + 53 + 543 + 3 = 666.

It is not a de Polignac number, because 53032535433 - 2² = 53032535429 is a prime.

It is a super-3 number, since 3×53032535433³ (a number of 33 digits) contains 333 as substring.

It is not an unprimeable number, because it can be changed into a prime (53032535473) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 982083963 + ... + 982084016.

It is an arithmetic number, because the mean of its divisors is an integer number (9820839900).

Almost surely, 2^53032535433 is an apocalyptic number.

It is an amenable number.

53032535433 is a deficient number, since it is larger than the sum of its proper divisors (25534183767).

53032535433 is a wasteful number, since it uses less digits than its factorization.

53032535433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1964167988 (or 1964167982 counting only the distinct ones).

The product of its (nonzero) digits is 243000, while the sum is 36.

The spelling of 53032535433 in words is "fifty-three billion, thirty-two million, five hundred thirty-five thousand, four hundred thirty-three".