Base | Representation |
---|---|
bin | 110001011001000001… |
… | …010110100000101011 |
3 | 12001212222012100102201 |
4 | 301121001112200223 |
5 | 1332102440242443 |
6 | 40210232041031 |
7 | 3555132126244 |
oct | 613101264053 |
9 | 161788170381 |
10 | 53033134123 |
11 | 20544904672 |
12 | a340833177 |
13 | 5002285948 |
14 | 27d14bdccb |
15 | 15a5cd134d |
hex | c5905682b |
53033134123 has 4 divisors (see below), whose sum is σ = 53502454008. Its totient is φ = 52563814240.
The previous prime is 53033134111. The next prime is 53033134139. The reversal of 53033134123 is 32143133035.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-53033134123 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 53033134091 and 53033134100.
It is not an unprimeable number, because it can be changed into a prime (53033134423) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 234659773 + ... + 234659998.
It is an arithmetic number, because the mean of its divisors is an integer number (13375613502).
Almost surely, 253033134123 is an apocalyptic number.
53033134123 is a deficient number, since it is larger than the sum of its proper divisors (469319885).
53033134123 is a wasteful number, since it uses less digits than its factorization.
53033134123 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 469319884.
The product of its (nonzero) digits is 9720, while the sum is 28.
Adding to 53033134123 its reverse (32143133035), we get a palindrome (85176267158).
The spelling of 53033134123 in words is "fifty-three billion, thirty-three million, one hundred thirty-four thousand, one hundred twenty-three".
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