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530340651 = 32123147869
BaseRepresentation
bin11111100111000…
…101101100101011
31100221221002121100
4133213011230223
52041231400101
6124343012443
716066551441
oct3747055453
91327832540
10530340651
112523aa865
1212973a123
1385b49149
1450612b91
153185ce86
hex1f9c5b2b

530340651 has 12 divisors (see below), whose sum is σ = 766685920. Its totient is φ = 353265840.

The previous prime is 530340637. The next prime is 530340659. The reversal of 530340651 is 156043035.

530340651 is a `hidden beast` number, since 5 + 3 + 0 + 3 + 4 + 0 + 651 = 666.

It is not a de Polignac number, because 530340651 - 27 = 530340523 is a prime.

It is a super-2 number, since 2×5303406512 = 562522412206207602, which contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (530340659) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 12856 + ... + 35013.

Almost surely, 2530340651 is an apocalyptic number.

530340651 is a deficient number, since it is larger than the sum of its proper divisors (236345269).

530340651 is a wasteful number, since it uses less digits than its factorization.

530340651 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 49106 (or 49103 counting only the distinct ones).

The product of its (nonzero) digits is 5400, while the sum is 27.

The square root of 530340651 is about 23029.1261449496. The cubic root of 530340651 is about 809.4405785199.

Adding to 530340651 its reverse (156043035), we get a palindrome (686383686).

It can be divided in two parts, 5303 and 40651, that added together give a palindrome (45954).

The spelling of 530340651 in words is "five hundred thirty million, three hundred forty thousand, six hundred fifty-one".

Divisors: 1 3 9 1231 3693 11079 47869 143607 430821 58926739 176780217 530340651