Base | Representation |
---|---|
bin | 100110100101100110010… |
… | …1101111000111011101001 |
3 | 200210000001202022210210111 |
4 | 1031023030231320323221 |
5 | 1143342403100200001 |
6 | 15140205350414321 |
7 | 1055105540056000 |
oct | 115131455707351 |
9 | 20700052283714 |
10 | 5303424225001 |
11 | 1765195795781 |
12 | 717a0a0613a1 |
13 | 2c615944b1c6 |
14 | 14498959dc37 |
15 | 92e4a820851 |
hex | 4d2ccb78ee9 |
5303424225001 has 16 divisors (see below), whose sum is σ = 6193941376000. Its totient is φ = 4539037474944.
The previous prime is 5303424224993. The next prime is 5303424225013. The reversal of 5303424225001 is 1005224243035.
It is not a de Polignac number, because 5303424225001 - 23 = 5303424224993 is a prime.
It is not an unprimeable number, because it can be changed into a prime (5303424225101) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 11256441 + ... + 11718118.
It is an arithmetic number, because the mean of its divisors is an integer number (387121336000).
Almost surely, 25303424225001 is an apocalyptic number.
It is an amenable number.
5303424225001 is a deficient number, since it is larger than the sum of its proper divisors (890517150999).
5303424225001 is an equidigital number, since it uses as much as digits as its factorization.
5303424225001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 22975253 (or 22975239 counting only the distinct ones).
The product of its (nonzero) digits is 28800, while the sum is 31.
Adding to 5303424225001 its reverse (1005224243035), we get a palindrome (6308648468036).
The spelling of 5303424225001 in words is "five trillion, three hundred three billion, four hundred twenty-four million, two hundred twenty-five thousand, one".
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