Base | Representation |
---|---|
bin | 100110100101100110100… |
… | …1101001010011111101011 |
3 | 200210000002022202022220000 |
4 | 1031023031031022133223 |
5 | 1143342412200022103 |
6 | 15140210242234043 |
7 | 1055105666543022 |
oct | 115131515123753 |
9 | 20700068668800 |
10 | 5303432423403 |
11 | 176519a385314 |
12 | 717a10955923 |
13 | 2c615b05ba2a |
14 | 14498a6d58b9 |
15 | 92e4b3deaa3 |
hex | 4d2cd34a7eb |
5303432423403 has 40 divisors (see below), whose sum is σ = 7930728748800. Its totient is φ = 3531911411952.
The previous prime is 5303432423381. The next prime is 5303432423423. The reversal of 5303432423403 is 3043242343035.
5303432423403 is a `hidden beast` number, since 5 + 3 + 0 + 3 + 4 + 3 + 242 + 3 + 403 = 666.
It is not a de Polignac number, because 5303432423403 - 29 = 5303432422891 is a prime.
It is not an unprimeable number, because it can be changed into a prime (5303432423423) by changing a digit.
It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 740802738 + ... + 740809896.
It is an arithmetic number, because the mean of its divisors is an integer number (198268218720).
Almost surely, 25303432423403 is an apocalyptic number.
5303432423403 is a deficient number, since it is larger than the sum of its proper divisors (2627296325397).
5303432423403 is a wasteful number, since it uses less digits than its factorization.
5303432423403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 15493 (or 15484 counting only the distinct ones).
The product of its (nonzero) digits is 311040, while the sum is 36.
Adding to 5303432423403 its reverse (3043242343035), we get a palindrome (8346674766438).
The spelling of 5303432423403 in words is "five trillion, three hundred three billion, four hundred thirty-two million, four hundred twenty-three thousand, four hundred three".
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