Base | Representation |
---|---|
bin | 1001111000001110… |
… | …10100101110000011 |
3 | 111200121111201220112 |
4 | 10330013110232003 |
5 | 41330200121011 |
6 | 2234132501535 |
7 | 245266114550 |
oct | 47407245603 |
9 | 14617451815 |
10 | 5303520131 |
11 | 2281776198 |
12 | 104017a8ab |
13 | 6669bc9c0 |
14 | 38450da27 |
15 | 21090d58b |
hex | 13c1d4b83 |
5303520131 has 16 divisors (see below), whose sum is σ = 6569002944. Its totient is φ = 4169453184.
The previous prime is 5303520077. The next prime is 5303520149. The reversal of 5303520131 is 1310253035.
It is a de Polignac number, because none of the positive numbers 2k-5303520131 is a prime.
It is a super-2 number, since 2×53035201312 = 56254651559844514322, which contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 5303520097 and 5303520106.
It is not an unprimeable number, because it can be changed into a prime (5303520181) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 171320 + ... + 199893.
It is an arithmetic number, because the mean of its divisors is an integer number (410562684).
Almost surely, 25303520131 is an apocalyptic number.
5303520131 is a deficient number, since it is larger than the sum of its proper divisors (1265482813).
5303520131 is a wasteful number, since it uses less digits than its factorization.
5303520131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 371390.
The product of its (nonzero) digits is 1350, while the sum is 23.
The square root of 5303520131 is about 72825.2712387671. The cubic root of 5303520131 is about 1743.8993155610.
Adding to 5303520131 its reverse (1310253035), we get a palindrome (6613773166).
The spelling of 5303520131 in words is "five billion, three hundred three million, five hundred twenty thousand, one hundred thirty-one".
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