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530354054403 = 3258928228267
BaseRepresentation
bin1111011011110111001…
…00001010010100000011
31212200221021201102221200
413231323210022110003
532142131114220103
61043350303552243
753213445036645
oct7557344122403
91780837642850
10530354054403
11194a16045878
12869525bb683
133b020988604
141b9526b2895
15dbe08970a3
hex7b7b90a503

530354054403 has 6 divisors (see below), whose sum is σ = 766066967484. Its totient is φ = 353569369596.

The previous prime is 530354054383. The next prime is 530354054407. The reversal of 530354054403 is 304450453035.

530354054403 is a `hidden beast` number, since 530 + 35 + 4 + 0 + 54 + 40 + 3 = 666.

530354054403 is digitally balanced in base 4, because in such base it contains all the possibile digits an equal number of times.

It is a de Polignac number, because none of the positive numbers 2k-530354054403 is a prime.

It is not an unprimeable number, because it can be changed into a prime (530354054407) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 29464114125 + ... + 29464114142.

It is an arithmetic number, because the mean of its divisors is an integer number (127677827914).

Almost surely, 2530354054403 is an apocalyptic number.

530354054403 is a deficient number, since it is larger than the sum of its proper divisors (235712913081).

530354054403 is a wasteful number, since it uses less digits than its factorization.

530354054403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 58928228273 (or 58928228270 counting only the distinct ones).

The product of its (nonzero) digits is 216000, while the sum is 36.

The spelling of 530354054403 in words is "five hundred thirty billion, three hundred fifty-four million, fifty-four thousand, four hundred three".

Divisors: 1 3 9 58928228267 176784684801 530354054403