Base | Representation |
---|---|
bin | 110001011001001010… |
… | …000011001011011001 |
3 | 12001220010111012011020 |
4 | 301121022003023121 |
5 | 1332104031223413 |
6 | 40210352553053 |
7 | 3555160403634 |
oct | 613112031331 |
9 | 161803435136 |
10 | 53035414233 |
11 | 2054612175a |
12 | a341552789 |
13 | 50028a3719 |
14 | 27d1914c1b |
15 | 15a60d1c23 |
hex | c592832d9 |
53035414233 has 8 divisors (see below), whose sum is σ = 74873526048. Its totient is φ = 33277122624.
The previous prime is 53035414231. The next prime is 53035414241. The reversal of 53035414233 is 33241453035.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 53035414233 - 21 = 53035414231 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 53035414194 and 53035414203.
It is not an unprimeable number, because it can be changed into a prime (53035414231) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 519954991 + ... + 519955092.
It is an arithmetic number, because the mean of its divisors is an integer number (9359190756).
Almost surely, 253035414233 is an apocalyptic number.
It is an amenable number.
53035414233 is a deficient number, since it is larger than the sum of its proper divisors (21838111815).
53035414233 is a wasteful number, since it uses less digits than its factorization.
53035414233 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1039910103.
The product of its (nonzero) digits is 64800, while the sum is 33.
Adding to 53035414233 its reverse (33241453035), we get a palindrome (86276867268).
The spelling of 53035414233 in words is "fifty-three billion, thirty-five million, four hundred fourteen thousand, two hundred thirty-three".
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