Search a number
-
+
5303541497 = 19279133763
BaseRepresentation
bin1001111000001110…
…11001111011111001
3111200121112211012212
410330013121323321
541330201311442
62234133144505
7245266234052
oct47407317371
914617484185
105303541497
112281790251
12104018b135
136669c9647
14384517729
15210914a82
hex13c1d9ef9

5303541497 has 4 divisors (see below), whose sum is σ = 5582675280. Its totient is φ = 5024407716.

The previous prime is 5303541487. The next prime is 5303541521. The reversal of 5303541497 is 7941453035.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 5303541497 - 214 = 5303525113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (5303541437) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 139566863 + ... + 139566900.

It is an arithmetic number, because the mean of its divisors is an integer number (1395668820).

Almost surely, 25303541497 is an apocalyptic number.

It is an amenable number.

5303541497 is a deficient number, since it is larger than the sum of its proper divisors (279133783).

5303541497 is a wasteful number, since it uses less digits than its factorization.

5303541497 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 279133782.

The product of its (nonzero) digits is 226800, while the sum is 41.

The square root of 5303541497 is about 72825.4179322028. The cubic root of 5303541497 is about 1743.9016574083.

The spelling of 5303541497 in words is "five billion, three hundred three million, five hundred forty-one thousand, four hundred ninety-seven".

Divisors: 1 19 279133763 5303541497