Base | Representation |
---|---|
bin | 11000000111100010100110… |
… | …11101000100011111101011 |
3 | 20221210011022002001021121001 |
4 | 30003301103131010133223 |
5 | 23422414011003104043 |
6 | 304444124423055431 |
7 | 14112462001266151 |
oct | 1403612335043753 |
9 | 227704262037531 |
10 | 53035656300523 |
11 | 15998328388126 |
12 | 5b467b9ba1577 |
13 | 2379319425550 |
14 | d14d21c4b3d1 |
15 | 61e8a487374d |
hex | 303c537447eb |
53035656300523 has 4 divisors (see below), whose sum is σ = 57115322169808. Its totient is φ = 48955990431240.
The previous prime is 53035656300493. The next prime is 53035656300589. The reversal of 53035656300523 is 32500365653035.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-53035656300523 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (53035656390523) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2039832934623 + ... + 2039832934648.
It is an arithmetic number, because the mean of its divisors is an integer number (14278830542452).
Almost surely, 253035656300523 is an apocalyptic number.
53035656300523 is a deficient number, since it is larger than the sum of its proper divisors (4079665869285).
53035656300523 is a wasteful number, since it uses less digits than its factorization.
53035656300523 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4079665869284.
The product of its (nonzero) digits is 3645000, while the sum is 46.
The spelling of 53035656300523 in words is "fifty-three trillion, thirty-five billion, six hundred fifty-six million, three hundred thousand, five hundred twenty-three".
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